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A-Level Integration: From Antiderivatives to Areas

An intuitive exploration of integration covering power rules, substitution, integration by parts, definite integrals as areas, and standard function results.

Integration: The Reverse ProcessDifferentiationIntegration (Reversal)
∫xndx=xn+1n+1+C\int x^n dx = \frac{x^{n+1}}{n+1} + C
Think of integration as unwinding the process of differentiation. If differentiation tells us the slope, integration asks us to recover the original function from that slope.
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1

(a) Basic Integration

Use the reverse power rule on each term of the polynomial.

∫(3x2+4x−5)dx=x3+2x2−5x+C\int (3x^2+4x-5) dx = x^3 + 2x^2 - 5x + C
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(b) Substitution

Identify the inner function u and substitute, noting that du accounts for the derivative factor.

∫2x(x2+1)5dx=(x2+1)66+C\int 2x(x^2+1)^5 dx = \frac{(x^2+1)^6}{6} + C
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(c) Parts

Assign u and dv according to LIATE, then apply the formula.

∫xexdx=xex−ex+C\int x e^x dx = x e^x - e^x + C
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(d) Definite Integral

Evaluate the antiderivative at the upper limit 3 and subtract the evaluation at 1.

[x33]13=273−13=263[\frac{x^3}{3}]_1^3 = \frac{27}{3} - \frac{1}{3} = \frac{26}{3}
5

(e) Standard Functions

Apply standard integral results for each function type individually.

∫(sin⁡x+e2x+1x)dx=−cos⁡x+12e2x+ln⁡∣x∣+C\int (\sin x + e^{2x} + \frac{1}{x}) dx = -\cos x + \frac{1}{2}e^{2x} + \ln|x| + C

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A-Level integration explained

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