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Understanding Data and Divisibility

A journey through interpreting temperature extremes, calculating averages with negatives, and discovering factors in group logistics.

Temperature Scale (°C)-54Range: 9
4−(−5)=4+5=94 - (-5) = 4 + 5 = 9
Think of the range as the total gap between the hottest and coldest extremes. When one extreme is negative, subtracting it is just like adding its positive distance from zero.
Step-by-step solver
1

(a) Temperature Range

Subtract the lowest temperature from the highest. Remember that subtracting a negative is equivalent to adding a positive.

4−(−5)=4+5=9∘C4 - (-5) = 4 + 5 = 9^{\circ}C
2

(b) Temperature Mean

Sum the temperatures and divide by the count of 6 readings.

−5−2+3+4−1+26=16≈0.17∘C\frac{-5-2+3+4-1+2}{6} = \frac{1}{6} \approx 0.17^{\circ}C
3

(c) Packing Tins

Divide the total tins by the capacity per box to find the number of full boxes.

156÷12=13 boxes (no remainder)156 \div 12 = 13 \text{ boxes (no remainder)}
4

(d) Highest Common Factor

Find the prime factors of 156 and 84, then identify the largest product common to both.

156=22×3×13; 84=22×3×7; HCF=22×3=12156 = 2^2 \times 3 \times 13;\, 84 = 2^2 \times 3 \times 7;\, \text{HCF} = 2^2 \times 3 = 12

Original question

functional maths level 2 numbers and negative numbers and multiple factors sample question and solution

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